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3v^2-6v+3=0
a = 3; b = -6; c = +3;
Δ = b2-4ac
Δ = -62-4·3·3
Δ = 0
Delta is equal to zero, so there is only one solution to the equation
Stosujemy wzór:$v=\frac{-b}{2a}=\frac{6}{6}=1$
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